http://gcc.gnu.org/bugzilla/show_bug.cgi?id=48934

--- Comment #7 from Jonathan Wakely <redi at gcc dot gnu.org> 2011-05-09 
16:24:51 UTC ---
(In reply to comment #6)

Oops, no, that's a mistake, the parameter should be named 't'

  template<typename T> struct S1 { typedef char type; };

  template<typename T>
    typename S1<T>::type
    foo(typename S1<T>::typo t)
    { return t; }

  char c = foo<int>(1);

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