C++98 [temp.local] says "Within the scope of a class template specialization or
partial specialization, when the name of the template is neither qualified nor
followed by <, it is equivalent to the name of the template followed by the
template-arguments enclosed in <>."  That does not work when a template
specialization is used as a base class.  In that case g++ does not accept the
unqualified base class name as a type.

This test case:

template <class T>
struct base {};

struct derived : base<int> {
  typedef base b;
  base* p;
};

gives these errors:

foo.cc:5: error: invalid use of template-name ‘base’ without an argument list
foo.cc:6: error: ISO C++ forbids declaration of ‘base’ with no type
foo.cc:6: error: expected ‘;’ before ‘*’ token

I believe this is an incorrect rejection of valid C++ code.  At least, I can't
find anything in the C++ standard which says that this code is invalid.


-- 
           Summary: Specialized template base class name not accepted
           Product: gcc
           Version: 4.4.0
            Status: UNCONFIRMED
          Keywords: rejects-valid
          Severity: normal
          Priority: P3
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: ian at airs dot com


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=37350

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