------- Comment #3 from christoph dot wintersteiger at inf dot ethz dot ch 2007-04-26 12:31 ------- (In reply to comment #2) > There is no implicit cast here. a[b] is the same as (*((a)+(b))), and since > addition is commutative, this is the same as (b)[a]. >
Thanks for clarifying. I still think it's completely confusing to have a[b]==b[a] in general, but that's probably something that can't be changed easily. -- http://gcc.gnu.org/bugzilla/show_bug.cgi?id=31712
