> Which part of: > > __builtin_isunordered(nan,nan) = 1 > __builtin_isnan(nan) = 0 > > is consistent?
Did you read what the options do because it seems like you did not and you keep on agruing that it is inconsistent except for the fact this is way these options are done as it just says "allows for optimizations" and not always assume finite math and ignore NaNs all the time. -- Pinski
