Julian Elischer <[EMAIL PROTECTED]> writes: > When did this come in? (I have been seeing it for a while but.. > I thought this was to save space on the bootblocks, not the entire > kernel?) > Do we really want shorts being pushed onto the stack as shorts? > (This is what this implies) No, the units are actually powers-of-two and that overrides the default of aligning for doubles (which would be useless in the kernel). To Unsubscribe: send mail to [EMAIL PROTECTED] with "unsubscribe freebsd-current" in the body of the message
- kernel: -mpreferred-stack-boundary=2 ?? Julian Elischer
- Re: kernel: -mpreferred-stack-boundary=2 ?? Marcel Moolenaar
- Re: kernel: -mpreferred-stack-boundary=2 ?? Daniel C. Sobral
- Re: kernel: -mpreferred-stack-boundary=... Marcel Moolenaar
- Re: kernel: -mpreferred-stack-boundary=... Peter Wemm
- Re: kernel: -mpreferred-stack-boundary=2 ?? Ville-Pertti Keinonen
- Re: kernel: -mpreferred-stack-boundary=2 ?? Marcel Moolenaar
- Re: kernel: -mpreferred-stack-boundary=2 ?? Ville-Pertti Keinonen
- Re: kernel: -mpreferred-stack-boundary=... Marcel Moolenaar
- Re: kernel: -mpreferred-stack-bound... Ville-Pertti Keinonen
- Re: kernel: -mpreferred-stack-... Matthew Dillon
- Re: kernel: -mpreferred-st... Marcel Moolenaar
- Re: kernel: -mpreferre... Matthew Dillon
- Re: kernel: -mpreferre... Marcel Moolenaar
- Re: kernel: -mpreferre... Bruce Evans
- Re: kernel: -mpreferre... Dmitrij Tejblum