Are you passing the keys as a filter or an argument? What does optimizeForWrite in your function return?
Thanks, Barry Oglesby On Mon, May 1, 2017 at 4:41 PM, Goutam Tadi <gt...@pivotal.io> wrote: > Hi Dan, > > Thanks for the reply. > No, we are neither executing the function nor passing keys from a client. > We are trying to remove a significant portion of the keys from a region > (most, but not all) at once. > > Thanks. > > On Mon, May 1, 2017 at 2:40 PM Dan Smith <dsm...@pivotal.io> wrote: > > > That seems like it should do things fairly quickly. Are you executing the > > function from a client? Did you find that using a function was actually > > faster than just calling removeAll from the client? I think removeAll > from > > the client should send your keys in a single message, similar to your > > function approach. > > > > How many keys are you trying to remove? If you have a really large number > > of keys, it might be better to batch up the keys. You could do multiple > > removeAlls from the client, perhaps even in parallel. > > > > -Dan > > > > On Mon, May 1, 2017 at 12:19 PM, Goutam Tadi <gt...@pivotal.io> wrote: > > > > > Hi Team, > > > > > > With +Bradford D Boyle <bbo...@pivotal.io> > > > > > > We are trying to remove a set of keys from a `PartitionedRegion`. > > > Currently, we execute a function with `onRegion()`. Inside the > function, > > we > > > call `PartitionRegionHelper.getLocalPrimaryData()` and use the > returned > > > region to execute `region.removeAll(keys)`. > > > > > > The problem we are facing is that is slow. Is there a faster way to > > remove > > > a set of keys from a partitioned region? > > > > > > We are considering using `getDataStore().getAllLocalBucketRegions()` > to > > > get > > > the set of `BucketRegion`s and then using a thread pool to remove the > > keys > > > in parallel. Are there alternative approaches? > > > > > > Thanks, > > > Goutam Tadi. > > > -- > > > Regards, > > > *Goutam Tadi.* > > > > > > -- > Regards, > *Goutam Tadi.* >
