That seems like it should do things fairly quickly. Are you executing the function from a client? Did you find that using a function was actually faster than just calling removeAll from the client? I think removeAll from the client should send your keys in a single message, similar to your function approach.
How many keys are you trying to remove? If you have a really large number of keys, it might be better to batch up the keys. You could do multiple removeAlls from the client, perhaps even in parallel. -Dan On Mon, May 1, 2017 at 12:19 PM, Goutam Tadi <gt...@pivotal.io> wrote: > Hi Team, > > With +Bradford D Boyle <bbo...@pivotal.io> > > We are trying to remove a set of keys from a `PartitionedRegion`. > Currently, we execute a function with `onRegion()`. Inside the function, we > call `PartitionRegionHelper.getLocalPrimaryData()` and use the returned > region to execute `region.removeAll(keys)`. > > The problem we are facing is that is slow. Is there a faster way to remove > a set of keys from a partitioned region? > > We are considering using `getDataStore().getAllLocalBucketRegions()` to > get > the set of `BucketRegion`s and then using a thread pool to remove the keys > in parallel. Are there alternative approaches? > > Thanks, > Goutam Tadi. > -- > Regards, > *Goutam Tadi.* >
