A E [Gmail] put forth on 4/8/2011 10:58 AM: > #> time nice fakeroot make-kpkg --subarch=sun4u --arch_in_name > --revision=2.6.32-5-Cust001 --initrd kernel_image
> The question is, if I allowed it to slap on the arch in name automatically > and it ended up calling it 'sparc', does that mean it's created a 32-bit > kernel and not 64-bit as I'd have expected it to end with 'sparc64'. The package naming is irrelevant to the contents of the binary kernel file you generated. It is simply a file name. "--subarch=sun4u" dictates the resulting kernel binaries contain 64bit UltraSPARC instructions, or "SPARC v9" instructions. You have created a custom 64bit SPARC Linux kernel. The naming is simply to remind you of what's in it when you look at that file a year from now, especially amongst a group of 6 other similar kernels you've created. -- Stan -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of "unsubscribe". Trouble? Contact listmas...@lists.debian.org Archive: http://lists.debian.org/4d9f33a5.3030...@hardwarefreak.com
