Hello All, I've made a first attempt at trying to change some config of the stock kernel for squeeze on sparc64. Went through the instructions found somewhere on the net and on the debian wiki, and have ended up with a kernel package.
Command used was: #> time nice fakeroot make-kpkg --subarch=sun4u --arch_in_name --revision=2.6.32-5-Cust001 --initrd kernel_image Have ended up with a deb package called: linux-image-2.6.32-sun4u_2.6.32-Cust001_sparc.deb The question is, if I allowed it to slap on the arch in name automatically and it ended up calling it 'sparc', does that mean it's created a 32-bit kernel and not 64-bit as I'd have expected it to end with 'sparc64'. #> uname -m sparc64 Thanks AEG
