#(fn fib [x] ... ) creates a zero-arity function which, when called, will
return a one-arity function. Just get rid of the #.


On Wed, Nov 13, 2013 at 9:41 AM, Angus <[email protected]> wrote:

> I know this fibonacci function is not optimal but I want to learn one step
> at a time.  I want to be able to apply this approach to 4clojure which
> disallows a lot of things including defn.
>
> This is my implementation so far:
>
> (defn fib [x]
>    (cond
>       (= x 0) 0
>       (= x 1) 1
>       :else
>          (+ (fib (- x 1)) (fib (- x 2)))))
>
>
> So I thought about something like this:
>
> (#(fn fib [x]
>    (cond
>       (= x 0) 0
>       (= x 1) 1
>       :else
>          (+ (fib (- x 1)) (fib (- x 2)))))
>               8)
>
> But trying that in a REPL I get error:
>
> clojure.lang.ArityException: Wrong number of args (1) passed to:
> sandbox28956$eval28971$fn
>
> So how can I call this as a one line REPL?
>
> I though using apply with a one element list might work, but no.
>
> (apply #(fn fib [x](cond (= x 0) 0 (= x 1) 1  :else  (+ (fib (- x 1)) (fib
> (- x 2))))) '(8))
>
>
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-- 
Ben Wolfson
"Human kind has used its intelligence to vary the flavour of drinks, which
may be sweet, aromatic, fermented or spirit-based. ... Family and social
life also offer numerous other occasions to consume drinks for pleasure."
[Larousse, "Drink" entry]

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