I know this fibonacci function is not optimal but I want to learn one step
at a time. I want to be able to apply this approach to 4clojure which
disallows a lot of things including defn.
This is my implementation so far:
(defn fib [x]
(cond
(= x 0) 0
(= x 1) 1
:else
(+ (fib (- x 1)) (fib (- x 2)))))
So I thought about something like this:
(#(fn fib [x]
(cond
(= x 0) 0
(= x 1) 1
:else
(+ (fib (- x 1)) (fib (- x 2)))))
8)
But trying that in a REPL I get error:
clojure.lang.ArityException: Wrong number of args (1) passed to:
sandbox28956$eval28971$fn
So how can I call this as a one line REPL?
I though using apply with a one element list might work, but no.
(apply #(fn fib [x](cond (= x 0) 0 (= x 1) 1 :else (+ (fib (- x 1)) (fib
(- x 2))))) '(8))
--
--
You received this message because you are subscribed to the Google
Groups "Clojure" group.
To post to this group, send email to [email protected]
Note that posts from new members are moderated - please be patient with your
first post.
To unsubscribe from this group, send email to
[email protected]
For more options, visit this group at
http://groups.google.com/group/clojure?hl=en
---
You received this message because you are subscribed to the Google Groups
"Clojure" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
For more options, visit https://groups.google.com/groups/opt_out.
