On Sat, Jan 19, 2013 at 7:02 PM, Colin Yates <[email protected]> wrote:
> user=> (defn stream1 [] repeatedly create-user)
>
This function invokes neither repeatedly nor create-user. It pointlessly
refers to repeatedly and then returns a reference to the create-user
function.
Which is function and not a sequence, which is why you cannot take n from
it.
user=> (defn stream2 [] (repeatedly create-user))
>
> This function invokes repeatedly with a reference to create-user and
returns a lazy-sequence, which you can take n from.
> In other words, what effect does wrapping the function body in quotes
actually do?
By quotes I assume you mean ()'s. The answer is above. in stream1 you are
simply refering to functions. Without the ()'s
you're not invoking anything.
Compare:
user> create-user
#<user$create_user user$create_user@3f8ecde>
to:
user> (create-user)
{:id 1}
user>
/S
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