I am struggling to understand what Clojure is doing. This is definitely a
newbie question but I cannot figure it out :). The question is best asked
via a repl session:
[code]user=> (defn create-user [] {:id 1})
#'user/create-user
user=> (create-user)
{:id 1}
user=> (take 10 (repeatedly create-user))
({:id 1} {:id 1} {:id 1} {:id 1} {:id 1} {:id 1} {:id 1} {:id 1} {:id 1}
{:id 1})
user=> (defn stream1 [] repeatedly create-user)
#'user/stream1
user=> (take 10 stream1)
IllegalArgumentException Don't know how to create ISeq from: user$stream1
clojure.lang.RT.seqFrom (RT.java:494)
user=> (take 10 (stream1))
IllegalArgumentException Don't know how to create ISeq from:
user$create_user clojure.lang.RT.seqFrom (RT.java:494)
user=> (defn stream2 [] (repeatedly create-user))
#'user/stream2
user=> (take 10 stream2)
IllegalArgumentException Don't know how to create ISeq from: user$stream2
clojure.lang.RT.seqFrom (RT.java:494)
user=> (take 10 (stream2))
({:id 1} {:id 1} {:id 1} {:id 1} {:id 1} {:id 1} {:id 1} {:id 1} {:id 1}
{:id 1})
[/code]
My question is two parted - what is the different between stream1 and
stream2 - what exactly do they return. And, based on that, why doesn't
(stream1) return a sequence. In other words, what effect does wrapping the
function body in quotes actually do?
I know I will kick myself when I get the answer, so please feel free to
cause me to receive a good kicking ;).
Thanks!
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