riccibruno added a comment.
> I don't know how could a `PredefinedExpression` lack the function name,
> probably @riccibruno or @rjmccall can help with this - according to D53605
> <https://reviews.llvm.org/D53605>.
A `PredefinedExpr` whose declaration context is dependent has no name (see
`Sema::BuildPredefinedExpr`). Example:
void f0() { __func__; }
-PredefinedExpr 0x6a76ba8 <col:13> 'const char [3]' lvalue __func__
`-StringLiteral 0x6a76b88 <col:13> 'const char [3]' lvalue "f0"
template <typename> void f1() { __func__; }
`-PredefinedExpr 0x6a76e78 <col:35> '<dependent type>' lvalue __func__
template void f1<int>();
-PredefinedExpr 0x6a77060 <col:35> 'const char [3]' lvalue __func__
`-StringLiteral 0x6a77040 <col:35> 'const char [3]' lvalue "f1"
Repository:
rG LLVM Github Monorepo
CHANGES SINCE LAST ACTION
https://reviews.llvm.org/D87004/new/
https://reviews.llvm.org/D87004
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