https://sourceware.org/bugzilla/show_bug.cgi?id=18703
--- Comment #10 from Cary Coutant <ccoutant at gmail dot com> --- >> 0000000000000000 T foo >> 0000000000000000 T foo@VERS_1.1 >> >> With the version script, gold sees the first of those (plain "foo") >> and makes it the default version (as, I think, it should). The second >> one is just seen as a second declaration, but it's already been marked >> the default. > > foo is versioned and only version specified is VERS_1.1, which is not > default version. It is wrong to create a default foo without being asked > to do so. In this example, "foo" is both unversioned and versioned. In response to the unversioned one, gold is creating a default version, as directed by the linker script. If "foo@VERS_1.1" were the only version of "foo" in this file, gold would not make it a default version. If you don't want a default version, get rid of the first, unversioned, "foo", and gold will do what you expect. I've played around with a bunch of different combinations, and I can't even begin to unravel the logic behind Gnu ld's behavior when there are multiple instances of versioned and unversioned symbols. I have no desire to try to reproduce its behavior beyond what's described in the documentation. -cary -- You are receiving this mail because: You are on the CC list for the bug. _______________________________________________ bug-binutils mailing list bug-binutils@gnu.org https://lists.gnu.org/mailman/listinfo/bug-binutils
