I wanted to verify that this behavior is intended, as I can't find it
described in the manual.
$ echo $BASH_VERSION
4.3.30(1)-release
$ foo=bar
$ echo $foo
bar
$ bar=123
$ echo $bar
123
$ typeset -n foo
$ echo $foo
123
$ echo ${!foo} # this is what I want to verify
bar
Is using ${!foo} intended to yield the name of the var that foo references,
now that foo has been turned into a nameref? I wanted to use this
functionality in a script, but wanted to make sure it was intentional
before I rely on it.
Thanks,
-Jonathan Hankins
--
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Jonathan Hankins Homewood City Schools
The simplest thought, like the concept of the number one,
has an elaborate logical underpinning. - Carl Sagan
jhank...@homewood.k12.al.us
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