man 3 printf describes the following:
o An optional field, consisting of a decimal digit string followed
by a $, specifying the next argument to access. If this field is not
provided,
the argument following the last argument accessed will be used.
Arguments are numbered starting at 1. If unaccessed arguments in the format
string are interspersed with ones that are accessed the results
will be indeterminate.
This is a useful feature, allowing you to decouple the order of your
arguments with from the format. This is useful for localization and a few
other cases. In this example, I'd like to use it to simplify a regex
replace statement:
# s/(.*)foo(.*)/$2bar$1/
[[ 123foo567 =~ (.*)foo(.*) ]] && printf '%2$sbar%1$s'
"${BASH_REMATCH[@]:1}"
Is there a particular reason why bash's built-in printf does not support
this format modifier? Does bash re-implement printf or does it use the
Standard C Library's printf? (If the former; why?)
--
*Maarten Billemont* (lhunath)
me: http://www.lhunath.com – business: http://www.lyndir.com –
http://masterpasswordapp.com
