Chet Ramey wrote:
seba wrote:
GNU bash, version 3.2.25(1)-release (i686-pc-linux-gnu)
Copyright (C) 2005 Free Software Foundation, Inc.
#!/bin/sh
fib() {
n=$1
[ $n == 0 -o $n == 1 ] && return $n
fib $(($n-1))
ret1=$?
fib $(($n-2))
ret2=$?
return $(($ret1 + $ret2))
}
for ((i=0;$i<36;i++))
do
fib $i
echo "n=$i=>$?"
done
You managed to write yourself an infinitely-recursive function, and
eventually ran out of stack space. `==' is a string operator, not a
numeric operator, when used with `['.
Why is [ 0 == 0 ] any more or less true than [ 0 -eq 0 ]?
The problem seems to be that this line is missing from the function:
local n ret1 ret2
Oh, and return values wrap at 255, so using the return code only works
up to n=13. Use substitution ($()) and have the function 'echo' the result.
--
Matthew
"Who wants to sing?" -- Orcs (Warcraft II)
