Configuration Information [Automatically generated, do not change]:
Machine: i686
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i686'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i686-pc-linux-gnu'
-DCONF_VENDOR='pc' -DSHELL -DHAVE_CONFIG_H -D_GNU_SOURCE -I. -I. -I./include
-I./lib -O2 -march=i386 -mcpu=i686
uname output: Linux acsvan0 2.4.18-4custom #3 Fri May 31 14:54:10 EDT 2002 i686
unknown
Machine Type: i686-pc-linux-gnu
Bash Version: 2.05a
Patch Level: 0
Release Status: release
Description:
A shell script which worked perfectly using "1.14.7(1)" fails to execute
properly using "2.05a.0(1)-release". The purpose of the script is to parse
a session log file found in each user's home directory, and determine
whether a record belonging to some other user appears with today's date in
the file.
The parsing is done by gawk, using variables passed to it by repeated use
of the "-v" parameter.
I have tried this with both gawk 3.0.6 and gawk 3.1.1, and I get the same
results with either gawk. When I use bash 1.14, bash calls gawk correctly
and gives it the proper parameters. When I use bash 2.05a, each invocation
of gawk produces an error msg saying that gawk cannot open a file named
"-v".
Repeat-By:
Create files named "session_log" in the home directories of some users,
and run the script.
The shell script follows:
.....cut here.....
#!/bin/sh
blockflag=/ihome/tables/modemhog.txt
pageflag=/ihome/tables/modemhog.page
[ -s $blockflag ] && exit
for i in /home/*
do
[ -d $i ] || continue
cd $i
[ -f session_log ] || continue
tail session_log |
gawk -v Username=`basename $i` -v TodayDate=`date '+%b %e'` \
-v CurrentYear=`date '+%Y'` -v BlockFlag=$blockflag \
'$0 ~ /[Uu]ser/ && $0 !~ Username && $0 ~ TodayDate \
&& $0 ~ CurrentYear \
{print Username, $0 >> BlockFlag}'
done
[ -s $blockflag ] || exit 0
cat $blockflag
cp -f $blockflag $pageflag
.....cut here.....
NEIL PARKS
Beachwood, Ohio
