[EMAIL PROTECTED] wrote:
> Configuration Information [Automatically generated, do not change]:
> Machine: i686
> OS: linux-gnu
> Compiler: gcc
> Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i686'
> -DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i686-pc-linux-gnu'
> -DCONF_VENDOR='pc' -DSHELL -DHAVE_CONFIG_H -D_GNU_SOURCE -I. -I.
> -I./include -I./lib -O2 -march=i386 -mcpu=i686
> uname output: Linux acsvan0 2.4.18-4custom #3 Fri May 31 14:54:10 EDT 2002
> i686 unknown
> Machine Type: i686-pc-linux-gnu
>
> Bash Version: 2.05a
> Patch Level: 0
> Release Status: release
>
> Description:
> A shell script which worked perfectly using "1.14.7(1)" fails to execute
> properly using "2.05a.0(1)-release". The purpose of the script is to parse
> a session log file found in each user's home directory, and determine
> whether a record belonging to some other user appears with today's date in
> the file.
Why not run bash with the -x option to get an execution trace?
Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
Live Strong. No day but today.
Chet Ramey, ITS, CWRU [EMAIL PROTECTED] http://cnswww.cns.cwru.edu/~chet/
