HAHAHAHAHAHA!!!!!
-Chris
On Friday 06 December 2002 03:51 pm, [EMAIL PROTECTED] wrote:
> He forgot to mention the:
>
> use Advil;
>
> $pills = new Advil(2);
> unless($pills->take(orally)) {
> sleep 40;
> }
>
> http://danconia.org
>
>
> ------------------------------------------------
>
> On Fri, 6 Dec 2002 16:22:19 -0500 (EST), "Jeff 'japhy' Pinyan"
<[EMAIL PROTECTED]> wrote:
> > On Dec 6, Paul Johnson said:
> > >On Fri, Dec 06, 2002 at 11:58:37AM -0500, Danny Miller wrote:
> > >> Strictly speaking, ++$count is faster than $count++.
> > >
> > >Strictly speaking, perl will convert $count++ to ++$count if it can.
> >
> > Strictly speaking, there is another major difference no one has mentioned
> > yet (and that many people might have trouble understanding). Using
> > $count++ returns a NUMBER OR STRING, and then increments $count's value.
> > ++$count increments $count's value, and returns THE SCALAR ITSELF.
> >
> > How does this matter? Well, watch:
> >
> > $i = 2;
> > $j = ++$i / ++$i;
> >
> > What do you think $j will be? 3/4? Nope. 4/4, or 1. The reason is
> > because the ++$i form is a "footnote" type of thing. Basically it means
> > "increment $i, but leave $i here" whereas $i++ means "return $i's value,
> > and then increment it".
> >
> > Want to have your mind hurt?
> >
> > $i = 2;
> > @j = (++$i, ++$i, ++$i);
> >
> > What do you think @j will be? (5,5,5)? Yes, it will. The elements of
> > the list ARE $i themselves, and each element's expression increments $i
> > once; so $i becomes 5, and then the list is ($i, $i, $i), and all those
> > are 5. (Contrast this with ($i++, $i++, $i++), where the list is
> > (2,3,4), NOT ($i,$i,$i).)
> >
> > Here's the brain-hurting:
> >
> > $i = 2;
> > $j = ++$i + ++$i + ++$i;
> >
> > What do you think $j will be? 3 + 4 + 5 = 12? No. 5 + 5 + 5 = 15? No.
> > (NO!?) It will be 13. 4 + 4 + 5. HOW does Perl manage that? It's
> > because ++$i isn't executed until it's reached, and the THIRD one isn't
> > reached until the first two have been evaluated:
> >
> > $j = (++$i + ++$i) + ++$i;
> > # ++$i sets $i to 3
> > # ++$i sets $i to 4
> > # ($i + $i) returns 8
> > # ++$i sets $i to 5
> > # 8 + $i returns 15
> >
> > CRAZY. Or logical. Both, really.
> >
> > Oops. This is [EMAIL PROTECTED] Sorry. ;)
> >
> > --
> > Jeff "japhy" Pinyan [EMAIL PROTECTED]
> > http://www.pobox.com/~japhy/ RPI Acacia brother #734
> > http://www.perlmonks.org/ http://www.cpan.org/ <stu> what does y///
> > stand for? <tenderpuss> why, yansliterate of course. [ I'm looking for
> > programming work. If you like my work, let me know. ]
> >
> >
> > --
> > To unsubscribe, e-mail: [EMAIL PROTECTED]
> > For additional commands, e-mail: [EMAIL PROTECTED]
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