He forgot to mention the:
use Advil;
$pills = new Advil(2);
unless($pills->take(orally)) {
sleep 40;
}
http://danconia.org
------------------------------------------------
On Fri, 6 Dec 2002 16:22:19 -0500 (EST), "Jeff 'japhy' Pinyan" <[EMAIL PROTECTED]>
wrote:
> On Dec 6, Paul Johnson said:
>
> >On Fri, Dec 06, 2002 at 11:58:37AM -0500, Danny Miller wrote:
> >
> >> Strictly speaking, ++$count is faster than $count++.
> >
> >Strictly speaking, perl will convert $count++ to ++$count if it can.
>
> Strictly speaking, there is another major difference no one has mentioned
> yet (and that many people might have trouble understanding). Using
> $count++ returns a NUMBER OR STRING, and then increments $count's value.
> ++$count increments $count's value, and returns THE SCALAR ITSELF.
>
> How does this matter? Well, watch:
>
> $i = 2;
> $j = ++$i / ++$i;
>
> What do you think $j will be? 3/4? Nope. 4/4, or 1. The reason is
> because the ++$i form is a "footnote" type of thing. Basically it means
> "increment $i, but leave $i here" whereas $i++ means "return $i's value,
> and then increment it".
>
> Want to have your mind hurt?
>
> $i = 2;
> @j = (++$i, ++$i, ++$i);
>
> What do you think @j will be? (5,5,5)? Yes, it will. The elements of
> the list ARE $i themselves, and each element's expression increments $i
> once; so $i becomes 5, and then the list is ($i, $i, $i), and all those
> are 5. (Contrast this with ($i++, $i++, $i++), where the list is (2,3,4),
> NOT ($i,$i,$i).)
>
> Here's the brain-hurting:
>
> $i = 2;
> $j = ++$i + ++$i + ++$i;
>
> What do you think $j will be? 3 + 4 + 5 = 12? No. 5 + 5 + 5 = 15? No.
> (NO!?) It will be 13. 4 + 4 + 5. HOW does Perl manage that? It's
> because ++$i isn't executed until it's reached, and the THIRD one isn't
> reached until the first two have been evaluated:
>
> $j = (++$i + ++$i) + ++$i;
> # ++$i sets $i to 3
> # ++$i sets $i to 4
> # ($i + $i) returns 8
> # ++$i sets $i to 5
> # 8 + $i returns 15
>
> CRAZY. Or logical. Both, really.
>
> Oops. This is [EMAIL PROTECTED] Sorry. ;)
>
> --
> Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
> RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
> <stu> what does y/// stand for? <tenderpuss> why, yansliterate of course.
> [ I'm looking for programming work. If you like my work, let me know. ]
>
>
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