At 01:34 PM 6/11/02 -0700, I wrote:
>At 04:26 PM 6/11/02 -0400, Alaric Joseph Hammell wrote:
>
>>How would I get rid of one trailing white space character in
>>$HASH{$key} and reassign the result
>
>If you're certain that the last character is a space:
>
> chop $HASH{$key};
>
>If it might not be a space, and you only want to get rid of the last
>character if it is a space:
>
> $HASH{$key} =~ s/ $//;
>Oops, I missed the "white" part of "white space". Then the question >is
>whether you intend "white space" to include newline. Assuming you >don't
>(which is Perl's definition of "white space"), then:
>
> $HASH{$key} =~ s/\s$//;
Ok, What I meant by "match" was "compare" or test for equality. Sorry for
the confusion.
But, could someone explain the meaning of the "$" in the above expression,
s/\s$// .
How would I incorporate in the expression the $string which occurs before
the white space? (is that what the "$" is for?)
Thank you for all the helpful responses,
Al
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