You should be getting something like 6527, assuming that all of the CPU use is in the same task. 65 would be .65 seconds.
-- Shmuel (Seymour J.) Metz http://mason.gmu.edu/~smetz3 ________________________________________ From: IBM Mainframe Assembler List <[email protected]> on behalf of Brian Westerman <[email protected]> Sent: Saturday, September 21, 2019 6:26 AM To: [email protected] Subject: Converting TIMEUSED macro output to printable time used I know I'm doing something wrong, but I can't get the output from TIMEUSED to give me a valid time used In the program I have TIMEUSED STORADR=DBLWD1 LM R0,R1,DBLWD1 SRDL R0,12 D R0,K10000 CVD R1,DBLWD2 STRING (DBLWD2+4,P,L),INTO=CPUTIME K10000 DC F'10000' What I end up with in CPUTIME is (in this case) 324 for a job that ran all of 3 seconds (wall clock time) when my job stats show: CPU: 0 HR 01 MIN 05.27 SEC SRB: 0 HR 00 MIN 06.53 SEC I should be getting something like 65 (unless SRB is included when I would expect 71) I am obviously doing something wrong. I tried it using load grande and got the same results, so I went back to LM. any help at all would be appreciated. Brian
