On Thu, Dec 2, 2010 at 09:26:27 -0800, James Jones wrote:
> + for (i = 0; i < NUM_VERSIONS; i++) {
> + if (supported_versions[i].major == rep.majorVersion &&
> + supported_versions[i].minor == rep.minorVersion) {
> + return &supported_versions[i];
> + }
> + }
> +
Should this look for the highest pair that has major == rep.majorVersion
and minor <= rep.minorVersion, so you don't need to add every minor
version that doesn't change the number of errors?
Cheers,
Julien
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