Hi,

i'm trying to do simple entity lookup by label (exact match), but i don't know 
the language of the label.

I know i can do something like the following, but it's terribly slow (timeout, 
no result):

select * where {
  ?s rdfs:label ?l .
  FILTER(str(?l) = "贝拉克·奥巴马").
}

e.g.
http://dbpedia.org/sparql?default-graph-uri=http%3A%2F%2Fdbpedia.org&qtxt=prefix+dbpedia%3A+%3Chttp%3A%2F%2Fdbpedia.org%2Fresource%2F%3E%0D%0Aselect+*+where+{%0D%0A++%3Fs+rdfs%3Alabel+%3Fl+.%0D%0A++FILTER%28str%28%3Fl%29+%3D+%22%E8%B4%9D%E6%8B%89%E5%85%8B%C2%B7%E5%A5%A5%E5%B7%B4%E9%A9%AC%22%29.%0D%0A}&format=text%2Fhtml&CXML_redir_for_subjs=121&CXML_redir_for_hrefs=&timeout=30000&debug=on



I already tried bif:contains like this:

select * where {
  ?s rdfs:label ?l .
  FILTER(bif:contains(?l, "贝拉克·奥巴马")).
}

e.g.
http://dbpedia.org/sparql?default-graph-uri=http%3A%2F%2Fdbpedia.org&qtxt=prefix+dbpedia%3A+%3Chttp%3A%2F%2Fdbpedia.org%2Fresource%2F%3E%0D%0Aselect+*+where+{%0D%0A++%3Fs+rdfs%3Alabel+%3Fl+.%0D%0A++FILTER%28bif%3Acontains%28%3Fl%2C+%22%E8%B4%9D%E6%8B%89%E5%85%8B%C2%B7%E5%A5%A5%E5%B7%B4%E9%A9%AC%22%29%29.%0D%0A}&format=text%2Fhtml&CXML_redir_for_subjs=121&CXML_redir_for_hrefs=&timeout=30000&debug=on

but this returns the following error (and it's actually not exactly what i 
want):

> Virtuoso 37000 Error XM029: Free-text expression, line 0: Invalid character 
> in free-text search expression, it may not appear outside quoted string at è
> 
> 
> SPARQL query:
> define sql:big-data-const 0 
> #output-format:text/html
> define sql:signal-void-variables 1 define input:default-graph-uri 
> <http://dbpedia.org> prefix dbpedia: <http://dbpedia.org/resource/>
> select * where {
>   ?s rdfs:label ?l .
>   FILTER(bif:contains(?l, "贝拉克·奥巴马")).
> }



So, is there a way for a performant exact literal search ignoring the language?

Or could you maybe just make the standard `str(?l) = "something"` way quick if 
`?l` is a literal?


Best,
Jörn


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