Hi Is there a way to get full status information for a disjoint working copy without performing "svn st" on each sub working copies? And without the use of external definition?
Example: setenv p `pwd` svnadmin create r svn -m "" mkdir file:///$p/r/common file:///$p/r/common/module1 file:///$p/r/common/module2 file:///$p/r/common/module3 svn -m "" mkdir --parents file:///$p/r/prod/prodA svn co file:///$p/r/prod/prodA wc svn co file:///$p/r/common/module1 wc/mod1 svn co file:///$p/r/common/module3 wc/mod3 touch wc/mod1/file.txt svn add wc/mod1/file.txt Now if I perform "svn st wc" I get the output: ? wc/mod1 ? wc/mod3 I.e. I do not see the added file under wc/mod1. I must perform "svn st wc/*" to see this file: A wc/mod1/file.txt If I set the property svn:externals on r/prod/prodA I can use "svn st wc" to see all modifications. But sometimes I do not want to set the property. Is there some other way to get "svn st wc" to show the complete status for the disjoint working copy? /Atle
