Ryan Schmidt wrote on Tue, Mar 26, 2013 at 05:40:22 -0500: > > On Mar 26, 2013, at 02:46, "Niemann, Hartmut" wrote: > > > I have a directory <stuff> with some files and a list of svn:external > > directories <stuff/one/>, <stuff/two/> and so on. > > I want to svn export <stuff> with the files in it and only one of the > > svn:externals, not the others. > > > > I do not want to refer to the repository where the externals are located > > in, because the script that does the > > Svn export should not (need to) know where they are. > > > > I tried to svn export --depth files stuff && svn export --depth infinity > > stuff/one, but this fails because this directory is not existent in the > > repository. > > > > Is it possible to svn export only one of several svn:external directories? > > Or should I export all and delete all the files I don't need? > > > > I don't think what you want is easily possible. You'll have to script it. > > You could export with all the externals and delete the ones you don't need, > as you suggest. > > Or you could export with no externals at all, then manually export the > ones you want. You say you don't want the script to need to know where > the externals are located, but it doesn't need to: it can look it up > from the svn:externals property using "svn propget".
Alternatively, on 1.7+, you can look for .svn directories instead of parsing the svn:externals property. Only the wc root and roots of externals will have .svn dirs.
