There's no need to use a fake name like "FOO" that. The "location"
attribute of the property task does exactly what is needed. For example:
<property name="abs-path"
location="/abc/def/ghi/jkl/mno/../../foo.htm"/>
<echo message="${abs-path}/>
This will echo out "/abc/def/ghi/foo.htm". See
http://ant.apache.org/manual/CoreTasks/property.html for details
Cheers,
Joe
On Wed, 2009-03-25 at 15:41 -0400, David Weintraub wrote:
> Try the "dirname" task. This will normalize a file name, but it will
> also give it the full directory path and not the relative path:
>
> <property name="file.name"
> value="this/that/the-other/../../is/a/test.txt"/>
>
> <dirname property="dirname" file="${file.name}/FOO"/>
> <echo message="This is the path: ${dirname}"/>
>
> will print out: "/home/dweintraub/this/is/a/test.txt".
>
> Notice I appended "FOO" on the path, so <dirname> would also include
> the file name too.
>
> On Wed, Mar 25, 2009 at 1:51 AM, jbmdharris <jbmdhar...@hotmail.com> wrote:
> >
> > Does anyone have any good examples of normalizing paths in files?
> >
> > I have files that have paths like this in them:
> >
> > ../../foo.htm
> >
> > Which I process to make fully-qualified like this:
> >
> > /abc/def/ghi/jkl/mno/../../foo.htm
> >
> > Now I want to normalize the fully-qualified paths to remove the "../" parts
> > to get a result like this:
> >
> > /abc/def/ghi/foo.htm
> >
> > I've found I can use <replaceregexp> like this to replace one set of "../"
> > pairs:
> >
> > <replaceregexp
> > match="${util.includeTagStartRegExp}(.*?)/([^/.]*?)/\.\./(.*?)${util.includeTagEndRegExp}"
> > replace="${util.includeTagStartRegExp}\1/\3${util.includeTagEndRegExp}"
> > flags="sg" byline="false">
> >
> > And if I enclose this in a for loop, I can call it multiple times to remove
> > multiple sets of "../" pairs. However, I don't like hardcoding the number
> > of loops. Because it would be complicated to actually scan the files to get
> > the maximum number of "../" path components, the simplest thing for me to
> > use as my loop count is the maximum depth of the directory tree. Is there a
> > way to compute this?
> >
> > I've tried looping over the directory tree, getting the directories,
> > stripping out everything that isn't a "/". However, I can't figure out how
> > to determine which of these strings is the longest inside a for loop so I
> > know what my loop count will be.
> >
> > --
> > View this message in context:
> > http://www.nabble.com/Normalizing-paths-in-files-tp22695672p22695672.html
> > Sent from the Ant - Users mailing list archive at Nabble.com.
> >
> >
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