Public bug reported:
Hi,
take this simple example:
```
#!/usr/bin/env python3
import argparse
def do_default(options):
print("default")
def do_build(options):
print("build")
if __name__ == '__main__':
parser = argparse.ArgumentParser()
subparsers = parser.add_subparsers()
parser.set_defaults(func=do_default)
build = subparsers.add_parser('build')
build.set_defaults(func=do_build)
options = parser.parse_args()
options.func(options)
```
On Ubuntu 14.04, without parameters it errors for missing command and
with the parameter "build" it prints "default", so the subcommand gets
ignored somehow.
If running this on ubuntu 15.04, it works as expected: Without
parameters, it prints "default". With the parameter "build" it prints
"build".
I couldn't track that to any upstream bug report, but it seems like a
issue was fixed and the fix needs to get backported to ubuntu 14.04.
** Affects: python3-defaults (Ubuntu)
Importance: Undecided
Status: New
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https://bugs.launchpad.net/bugs/1482303
Title:
python 3.4.0's argparse ignores subcommand
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