Can You, please, elaborate this "..Passing in Python is different than
in C or other languages..."
'Cause as far as I know - default major Python's implementation CPython
is written in C.
Joel Goldstick 於 08/05/2015 03:44 PM 寫道:
On Wed, Aug 5, 2015 at 3:53 AM, John Doe <z2...@bk.ru> wrote:
To pass by reference or by copy of - that is the question from hamlet.
("hamlet" - a community of people smaller than a village
python3.4-linux64)
xlist = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
i = 0
for x in xlist:
print(xlist)
print("\txlist[%d] = %d" % (i, x))
if x%2 == 0 :
xlist.remove(x)
print(xlist, "\n\n")
i = i + 1
So, catch the output and help, PLEASE, me improve the answer:
Does it appropriate ALWAYS reevaluate the terms of the list on each
iteration?
But if I want to pass a copy to FOR instead of a reference (as seen
from an
output) and reduce unreasonable reevaluation, what I must to do for
that?
You aren't passing anything. the for statement is in the same
namespace as the rest of the code. Passing in python is different
than in C or other languages.
A couple of comments:
setting i = 0, then incrementing at the end of the loop would more
pythonically be done with the enumerate function.
Its generally a bad idea to remove items from and iterable while
interating over it. I'm guessing that this is what is confusing you.
One way to remove items from a list is to create a new list, and
append items you want to it, skipping the ones you don't. You don't
really need the index at all since python interation protocol will
walk through the list for you without worrying about index values
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