On 02/06/15 15:15, Peter Otten wrote:
Not an optimization, but if the user enters neither Y nor N you might ask again instead of assuming Y.
He does. He only breaks if the user enters N
choice = input('Do you want to play again y/n: ') if choice.upper() == 'N': print('end of game') break elif choice.upper() != 'Y': print("invalid choice")
Y goes round again silently. Anything other than Y or N prints the error then tries again. -- Alan G Author of the Learn to Program web site http://www.alan-g.me.uk/ http://www.amazon.com/author/alan_gauld Follow my photo-blog on Flickr at: http://www.flickr.com/photos/alangauldphotos _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
