On 28/01/15 00:09, Mark Lawrence wrote:
To get round that you need to explicitly compare o_die1
to both values:
if (o_die1 > d_die1) or (o_die1 > d_die2):
I consider the chained comparisons shown here
https://docs.python.org/3/reference/expressions.html#not-in to be far
more Pythonic. It also avoids the superfluous brackets which always
drive me around the bend.
Sorry Mark, I'm missing something. How would chained comparisons work
for this case? Especially a not-in?
You can avoid the compound test using any() and a generator as per my
earlier post but I can't think how a chained test would work here?
But it is getting late...
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.amazon.com/author/alan_gauld
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