Whees Northbee wrote:
> If I have array a=[[60,70,1],[43,54,2],[87,67,3],[90,89,4],[12,4,5]] where
> [x,y,id] and I want to find if x=87 and y=67, and find which row is it,and
> I need to edit the id column with new value..
>
> I can search in first column using:
> if (x in a[:,0]):
> print('yes')
>
> how I can know index row so I can match if y same value with second
> column?
I needed some google hand-holding for this, so no warranties:
>>> import numpy as np
>>> a = np.array([[60,70,1],[43,54,2],[87,67,3],[87,89,4],[12,4,5]])
>>> a[:,:2] == [87,67]
array([[False, False],
[False, False],
[ True, True],
[ True, False],
[False, False]], dtype=bool)
>>> (a[:,:2] == [87,67]).all(axis=1)
array([False, False, True, False, False], dtype=bool)
>>> np.where((a[:,:2] == [87,67]).all(axis=1))
(array([2]),)
> And I search in numpy array document there is no function about
> edit, so how I can edit the value the third column/id column if I know
> which row?
Easy:
>>> a[2,2] = 123456
>>> a
array([[ 60, 70, 1],
[ 43, 54, 2],
[ 87, 67, 123456],
[ 87, 89, 4],
[ 12, 4, 5]])
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