this forms a list of integers
>>> [0]*5
[0, 0, 0, 0, 0]
what I think you want is something like:
>>> [[0] for i in range(5)]
[[0], [0], [0], [0], [0]]
(a list of lists)
>>> foo = [[0] for i in range(5)]
>>> foo[3].append('bar')
>>> foo
[[0], [0], [0], [0, 'bar'], [0]]
On Wed, Aug 20, 2014 at 3:56 PM, Marc Tompkins <marc.tompk...@gmail.com>
wrote:
> On Wed, Aug 20, 2014 at 1:38 PM, Terry--gmail <terry.kemme...@gmail.com>
> wrote:
> > Marc, my understanding is, is that:
> >
> > lens[col].append(len(item))
> >
> > -should be building a mirror image of my list of lists called catalog2,
> > which currently has 9 columns by x number of rows, and that we are
> plugging
> > into these positions, the sizes of all the elements in that block of
> data.
>
> What's important is how you defined lens:
> > lens = [0] * len(catalog2[0])
>
> That's a list of integers, as far as I can tell without running it
> (I'm away from an interpreter at the moment.) So no, you cannot do
> lens[col].append(whatever), because - as the error message said -
> 'int' object has no attribute 'append'.
>
> There might be some misunderstanding about what list.append(whatever)
> does - it adds "whatever" to the end of list. It does NOT assign
> values to elements that already exist; to do that, you need to do
> assignment by index. So maybe this is what you're looking for?:
> > lens[col] = len(item)
>
>
>
> > So, I completely don't understand why we would eliminate the positioning
> of
> > which list we are referencing in lens by saying:
> >
> > lens.append(len(item))
> >
> > It seems to me that, that statement would put the entire block of element
> > sizes into one list, and the next MAX statement would then yield only a
> > single number, which would be the largest size element it encounted in
> the
> > whole of catalog2!
> >
> > Or am I really missing the boat here? :)
>
> > lens.append(len(item))
> will append a single integer to lens. I'm afraid I don't quite follow
> the bit about "the next MAX statement", as I've lost the thread of
> what your larger project is trying to accomplish... In any case,
> max() _should_ only return a single number, no?
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