On Fri, Aug 15, 2014 at 10:46 AM, Terry--gmail <terry.kemme...@gmail.com> wrote:
(By the way - your indentation got flattened - cue the inevitable chorus of "DON'T POST TO THIS LIST IN HTML" - so this is my best-guess reconstruction.) > lens = [] > # pre-format the list called lens for maximum number of columns contained in > catalog2 > lens = [0] * len(catalog2[0]) > # map the largest sizes of each column into list 'lens' > col, line_number = 0, 0 > for line_number in range(len(catalog2)): > for col in range(len(catalog2[line_number])): > if lens[col] < len(catalog2[line_number][col]): > lens[col] = len(catalog2[line_number][col]) There are two separate issues here - the syntactic mistake that's giving you the error, and the non-Pythonic nature of "for col in range()" - let's deal with the first one. catalog2 is a list containing lines; line_number is a list containing integers. catalog2[line_number][col] is an integer; len(int) gives you a TypeError, as you've seen. I don't entirely understand what you're trying to do, so I can't tell you whether you want > if lens[col] < len(catalog2[line_number]): or > if lens[col] < catalog2[line_number][col]: but it's probably one or the other. Now, for the second issue - to take the length of a list and use that as the limit for a one-by-one crawl through the list is not the Python way. Rather than: > for line_number in range(len(catalog2)): use > for line_number, item in enumerate(catalog2): https://docs.python.org/3/tutorial/datastructures.html#looping-techniques _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
