On 09.07.2014 08:16, Alan Gauld wrote:
On 09/07/14 06:58, Alan Gauld wrote:
list1 = [1, 8, 15]
list2 = [2, 9, 16]
list3 = [[3, 4, 5, 6], [10, 11, 12, 13], [17, 18, 19, 20]]
list4 = [7, 14, 21]
I'm thinking something like
result = []
for L in (list1,list2,list3):
if isinstance(L,list)
result += L
else: result.append(L)
mebbe...
Too early in the morning...
There needs to be another loop around that.
for L in (list1,list2,list3):
for index in len(list1): #???
if isinstance(L[index],list)
result += L[index]
else: result.append(L[index])
double mebbe.
Anyway I'm off to work... :-)
The working solution closest to Alan's attempt appears to be:
list1 = [1, 8, 15]
list2 = [2, 9, 16]
list3 = [[3, 4, 5, 6], [10, 11, 12, 13], [17, 18, 19, 20]]
list4 = [7, 14, 21]
final = []
for outer in zip(list1, list2, list3, list4):
for inner in outer:
if isinstance(inner, list):
final.extend(inner)
else:
final.append(inner)
print (final)
but his general idea is right.
Best,
Wolfgang
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