Scott W Dunning <swdunn...@cox.net> Wrote in message:
>
> On Mar 1, 2014, at 12:47 AM, Ben Finney <ben+pyt...@benfinney.id.au> wrote:
>
>> You've bound the name âcurrent_guessâ to the user's input, but then do
>> nothing with it for the rest of the function; it will be discarded
>> without being used.
> Hmm, Iâm not quite sure I understand. I got somewhat confused because the
> directions were changed a little and current_guess was removed from the
> get_guess function. Is this more like what I should be doing?
>
> def get_guess(guess_number):
> raw_input(âPlease enter a guessâ)
> guess_number = int(guess_number)
> return (guess_number)
That block of code is a huge step backwards from what you already
had. So let's go back a step.
def get_guess(guess_number):
  print "(",guess_number,")""Plese enter a guess:"
  current_guess = raw_input()
  return int(guess_number
First thing to do is decide what that function is 'supposed' to
do. What do you suppose a caller might expect as a return value?
Once you've decided a description, write it down as a set of
comments (or docstring, but that's another lesson).
>
>>
>> Then, you use the parameter âguess_numberâ, create a new integer from
>> it, and return that integer. I think you've used the wrong name for the
>> âint()â parameter.
> Well, since there are no loops allowed Iâm guessing get_guess will be
> called 9 times.
It will be called (up to) 9 times even after you learn about
loops. It's called get_guess, not get_guesses.
> I believe guess_number is the number of tries the user has used.
> So;
> (1) Please enter a guess:
> (2) Please enter a guess:
If that's a specification, then add it to your comments above. I
would guess you're missing a print in the function.
--
DaveA
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