On Sun, Oct 27, 2013 at 2:39 AM, Albert-Jan Roskam <fo...@yahoo.com> wrote: > Hi, > > Why does the "executable" parameter default to sys.executable? Yesterday I > was surprised to see platform.architecture return "32bit" on a 64-bit > system, just because a 32-bit Python interpreter was installed. Wouldn't > this make more sense: > > import sys, platform > pf = sys.platform.lower()[:3] > executable = "iexplore.exe" if pf[:3] == "win" else "/bin/ls"
I think it's mainly because of avoiding choosing arbitrary programs, although they are most certainly guaranteed to be present. Besides, there are better ways to find the platform architecture, I think. os.uname() comes to mind. -Amit. _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
