# skip 5
if count == 5:
continue # means "Jump back to the top of the looop"
It is the reason. You yourself have mentioned it right inside the code!
On 7 April 2013 09:40, Dave Angel <da...@davea.name> wrote:
> On 04/06/2013 11:23 PM, Najam Us Saqib wrote:
>
>> Hi,
>>
>> Would you please help me by explaining that why " 5 " is skipped and not
>> printed in the following program?
>>
>>
> Seems to me the comments say it pretty well. The continue statement
> causes execution to continue at the while statement, which has the effect
> of skipping the print. Like Monopoly: go directly to jail, do not pass go.
>
>
> Thank you.
>> Najam.
>>
>> count = 0
>> while True:
>> count += 1
>> # end loop if count is greater than 10
>> if count > 10:
>> break # means "break out of the loop"
>> # skip 5
>> if count == 5:
>> continue # means "Jump back to the top of the looop"
>> print count
>>
>> raw_input("\n\nPress the enter key to exit.")
>>
>> Output:
>>
>> 1
>> 2
>> 3
>> 4
>> 6
>> 7
>> 8
>> 9
>> 10
>>
>>
>> Press the enter key to exit.
>>
>
> Incidentally, this looks like a transliteration of something written for
> some other language. An experienced Python programmer would never write it
> this way.
>
> I'd use something like (untested):
>
> for count in xrange(11):
> if count != 5:
> print count
>
> On the other hand, a course --teaching a C programmer to use Python--
> might well use this as an early example, showing you later how much
> elegantly it can be done.
>
>
> --
> DaveA
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*Sayan Chatterjee*
Dept. of Physics and Meteorology
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blog: www.blissprofound.blogspot.com
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