Hi guys can you tell me what is wrong with the second part of this code(elif
choice == '2'). When I type something other than 0-255, it correctly asks again
for an input but when I enter a number from 0-255 it does nothing :
def show_menu():
print("=======================")
print("1-binary to denary")
print("2-denary to binary")
print("3-exit")
print("=======================")
while True:
show_menu()
choice = input("please enter an option: ")
if choice == '1':
binary = input("Please enter a binary number: ")
denary = 0
place_value = 1
for i in binary [::-1]:
denary += place_value * int(i)
place_value *= 2
print("The result is",denary)
elif choice == '2':
denary2 = int(input("Please enter a denary number: "))
remainder = ''
while denary2 not in range(0,256):
denary2 = int(input("Please enter a denary number: "))
continue
while denary2 in range(0,256):
remainder = str(denary2 % 2) + remainder
denary2 >>= 1
print("The result is",remainder)
elif choice == '3':
break
elif choice not in '1' or '2' or '3':
print("Invalid input-try again!")
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
