On 01/22/2013 10:08 PM, Mitya Sirenef wrote:
On 01/22/2013 09:52 PM, anthonym wrote:
Hello All,
>
> I originally wrote this program to calculate and print the employee
> with the most hours worked in a week. I would now like to change this
> to calculate and print the hours for all 8 employees in ascending
> order.
>
> The employees are named employee 0 - 8
>
> Any ideas?
>
> Thanks,
> Tony
>
> Code below:
>
>
>
> # Create table of hours worked
>
> matrix = [
> [2, 4, 3, 4, 5, 8, 8],
> [7, 3, 4, 3, 3, 4, 4],
> [3, 3, 4, 3, 3, 2, 2],
> [9, 3, 4, 7, 3, 4, 1],
> [3, 5, 4, 3, 6, 3, 8],
> [3, 4, 4, 6, 3, 4, 4],
> [3, 7, 4, 8, 3, 8, 4],
> [6, 3, 5, 9, 2, 7, 9]]
>
> maxRow = sum(matrix[0]) # Get sum of the first row in maxRow
> indexOfMaxRow = 0
>
> for row in range(1, len(matrix)):
> if sum(matrix[row]) > maxRow:
> maxRow = sum(matrix[row])
> indexOfMaxRow = row
>
> print("Employee 7", indexOfMaxRow, "has worked: ", maxRow, "hours")
There is an issue with this program: it omits the first row.
No, it doesn't. The OP fills in item 0 in the initial values for maxRow
and indexOfMaxRow. Then he figures he can skip that row in the loop,
which is correct.
It's better to use enumerate, e.g.:
for n, row in enumerate(matrix): ...
To make the change you need, use list comprehension to make sums of all
rows, sort it (using list sort method); iterate over it using
enumerate() and print out "employee N, sum of hours:"
HTH, -m
--
DaveA
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