You can break the loop when you get a positive matches, and add a
variable where you can count the number of positive matches, if it's
equal to zero print 'not found'
On 24/10/2012 17:43, Saad Javed wrote:
Let me modify this example:
a = [['jimmy', '25', 'pancakes'], ['tom', '23', 'brownies'], ['harry',
'21', 'cookies']]
for i in a:
*b = i[0]*
if (i[1] == '25' or i[1] == '26'):
print *b*
else:
print 'Not found'
This will output:
*jimmy*
*Not found*
*Not found*
*
*
How do I print positive matches (*jimmy*) only and not (*Not found*).
I also want *Not found *to print only /once /if there are no positive
matches.
On Wednesday, October 24, 2012, Saad Javed wrote:
Hi,
a = [['jimmy', '25', 'pancakes'], ['tom', '23', 'brownies'],
['harry', '21', 'cookies']]
for i in a:
if (i[1] == '25' or i[1] == '26'):
print 'yes'
else:
print 'Not found'
This prints:
yes
not found
I want it to print "yes" for each positive match but nothing for a
negative match. However if all matches are negative, I want it to
print "Not found" once (That bit the code already does). I do I
get it to print "yes" only in a mix result situation?
Saad
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