> Look at what your timing code does:
> 
> start = time.time()
> for i in range(10000):
>      anagramSolution2(word,word)
>      end1 = time.time()
>      solu2 = end1 - start
> 
> 
> Translated into English:
> 
> * start the timer
> * iteration 1 begins
> * call the anagram function
> * grab the ending time
> * calculate the difference in time
> * iteration 2 begins
> * call the anagram function
> * grab the ending time
> * calculate the difference in time
> * iteration 3 begins
> * call the anagram function
> * grab the ending time
> * calculate the difference in time
> ... and so on ...
> * iteration 10000 begins
> * call the anagram function
> * grab the ending time
> * calculate the difference in time
> 
> and finally you are done. Do you see what you have done? You calculate
> the time difference 10000 times instead of once. What you want is:
> 
> * start the timer
> * iteration 1 begins
> * call the anagram function
> * iteration 2 begins
> * call the anagram function
> * iteration 3 begins
> * call the anagram function
> ... and so on ...
> * iteration 10000 begins
> * call the anagram function
> * grab the ending time
> * calculate the difference in time
> 
> You should calculate the difference in time ONCE, not 10000 times. so what 
> should be done then would be to make sure that the start and end time are 
> like this? for n in range(10, 101, 5):    word = mkword(n)    start = 
> time.time()    for i in range(10000):        anagramSolutionX(word,word,    
> end1 = time.time()    solu2 = end1 - start is that right?sorry if im making 
> this harder than it should be to me that would make sense because you would 
> be asking it to do it 10000 times before it would move on to the end time? 
> thanks again for all the help guysit means a lot 
> 
> 
> > to me it looks like it should be right but the one line i think
> >is supposed to increas exponentially
> 
> I'm not sure why you think that. I'm not saying that it shouldn't,
> but I honestly can't tell. The code is so convoluted that I'm not
> sure what it does without detailed study, but at a quick glance I
> can't see anything that would make one of the anagram functions
> take O(N**2) time.
> 
> 
> 
> -- 
> Steven
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