On Fri, Sep 14, 2012 at 8:37 AM, Emile van Sebille <em...@fenx.com> wrote:
>
>> source = source.remove('')
>
> To round things out, here's one way to do what I expect you're expecting:
>
> >>> r=range(10)
> >>> a = r.pop(r.index(4))
> >>> a
> 4
> >>> r
> [0, 1, 2, 3, 5, 6, 7, 8, 9]
Ray was probably thinking in terms of immutable objects such as strings:
>>> "1".replace('1', '2').replace('2', '3')
'3'
Since Python doesn't do in-place operations on strings, it has to
return a new object for each call to replace().
list.pop() returns a value, but Ray doesn't want the value. Splitting
on a single character leaves empty strings between consecutive runs of
the character (or at the edges). For example, splitting 'babbbab' on
'b' returns ['', 'a', '', '', 'a', '']. Ray is looping until all of
the empty strings have been removed from the list. It's a completely
in-place modification.
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