Thank you all for the answer. Below, i have pasted a sample code that shows what i am intending to do. The code fails at line 13 as numpy array dnt have a index attribute.
1 #!/usr/bin/env python 2 import numpy as np 3 4 a=np.array([1,2,3,4,5,6,7,8,9,10,11,12]) 5 6 b=np.reshape(a,(3,4)) 7 8 z=[100,101,102,103,104,106,107,108,109,110,111,112] 9 10 # loop over each row 11 for i1, d1 in enumerate(b): 12 # each x in d1 - value in z corresponding to index of x in d1 13 d1=[x-z[d1.index(x)] for x in d1] If d1 is a simple list, i can fetch the index of its element as d1.index(x). So i would like to know how can achieve the same with numpy array. Thanks once again, Bala On Fri, Sep 14, 2012 at 12:39 AM, Dave Angel <d...@davea.name> wrote: > On 09/13/2012 04:16 PM, Bala subramanian wrote: >> Friends, >> I have a 2D matrix (a numpy array) and i am looping over each row in >> the matrix. I would like to know how i can find the index of each >> element in a while looping a row. Is there any function in numpy. >> >> Thanks >> > > Perhaps you're asking a more general question. When iterating over a > collection, sometimes you not only want the object, but you also want > the index you might have used to fetch it. > > for row in rows: > dosomething with row > > for index, row in enumerate(rows): > dosomething with row and with index > > Now if rows be a list, or whatever numpy decides to call it, then you > can manipulate the particular one with rows[index]. > > > > -- > > DaveA > -- C. Balasubramanian _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
