On 6/28/2012 11:51 PM Joseph Hines said...
Hello. Sorry to bother you, but I'm self-teaching myself python, and
having difficulty with a script I'm writing to auto-calc various derived
stats for a PnP game I am hosting soon.
I need to pass a numeral result of a defined function to a "named" value
(not sure if that's what it's called)
The offending segment of code is this:
... and what's the offending error? (provide traceback details please)
Do you mean to be defining a function within a try-except structure? As
it stands you'll get a syntax error.
You've likely got an indetation issue on the line before except.
providing int_mod as some integer and reworking it to:
XP_Per_Level_Base = 20-int_mod
XP_Per_Level_Limit = 5
try:
def XP_Per_Level_Calc(XP_Per_Level_Base, XP_Per_Level_Limit):
if XP_Per_Level_Base < XP_Per_Level_Limit:
return XP_Per_Level_Limit
else:
return XP_Per_Level_Base
except ValueError:
print "Script B0RK3D, Link Shall Come to Town."
print "send him a message at
link6...@gmail.com<mailto:link6...@gmail.com>"
XP_Per_Level = XP_Per_Level_Calc(XP_Per_Level_Base, XP_Per_Level_Limit)
gets it going, dut all in all it looks to me like this is simply a max
function and could be written more simply as:
max(XP_Per_Level_Base,XP_Per_Level_Limit)
Emile
XP_Per_Level_Base = 20-int_mod
XP_Per_Level_Limit = 5
try:
def XP_Per_Level_Calc(XP_Per_Level_Base, XP_Per_Level_Limit):
if XP_Per_Level_Base < XP_Per_Level_Limit:
return XP_Per_Level_Limit
else:
return XP_Per_Level_Base
XP_Per_Level = XP_Per_Level_Calc(XP_Per_Level_Base, XP_Per_Level_Limit)
except ValueError:
print "Script B0RK3D, Link Shall Come to Town."
print "send him a message at link6...@gmail.com
<mailto:link6...@gmail.com>"
#Calcs XP per Level#
If you need the whole script, I'd be glad to send it to you, just
promise me not to divulge too many details of it
(It's regarding a custom PnP system that I'm planning on releasing under
the Open Gaming License, and I'd prefer not to risk it becoming a
proprietary system for someone I don't know)
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