> > Hi there .... I've just joined this list and thought I'd introduce
myself.
Welcome!
> > correct = 0
> > match = 0
> > wrong = 0
> > results = [correct, match, wrong]
> >
> > results = getflag(flag_1, results)
> > results = getflag(flag_2, results)
> > results = getflag(flag_3, results)
> > results = getflag(flag_4, results)
>> def getflag(thisflag, results):
>> if (thisflag == 2):
>> results[0] += 1
>> elif (thisflag == 1):
>> results[1] += 1
>> elif (thisflag == 0):
>> results[2] += 1
>> return(results)
>>
>> In c, I would have used switch and case, but I gather there is no direct
>> equivalent in Python ... But it works as is.
C switch is just a different way of doing an if/elif tree, I do not
really see any real difference. Although, if there is you can feel free
to enlighten me. :)
Unlike C, the parenthesis in if statements and returns are not necessary.
> if (thisflag == 2):
becomes
if thisflag == 2:
> return(results)
becomes
return results
Furthermore, the way Python binds names means that modifying the list
in getflags modifies it in the callee. No need to return and reassign
results.
>>> def foo(x):
... x[0] += 1
...
>>> bar = [ 1, 3, 4 ]
>>> foo( bar )
>>> print bar
[2, 3, 4]
>>> foo( bar )
>>> print bar
[3, 3, 4]
Be careful of "results = [0] * 3". This style works fine for immutable
types (int, float, str) but does not work as people new to Python think
it does.
>>> def foo(x):
... x[0][0] += 1
...
>>> bar = [ [0] ]*3
>>> print bar
[[0], [0], [0]]
>>> foo( bar )
>>> print bar
[[1], [1], [1]]
>>> foo( bar )
>>> print bar
[[2], [2], [2]]
This occurs because bar is a list containing 3 elements which are
all the exact same object. Modifying one sub-list will modify the
"others" as well.
Ramit
Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology
712 Main Street | Houston, TX 77002
work phone: 713 - 216 - 5423
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