On 2/7/2012 1:57 PM, Sarma Tangirala wrote:
Anyway, I was wondering about this, if internally pow() actually uses
**. :P
>>> from dis import dis
>>> dis(lambda a,b:a**b)
1 0 LOAD_FAST 0 (a)
3 LOAD_FAST 1 (b)
6 BINARY_POWER
7 RETURN_VALUE
>>> dis(lambda a,b:pow(a,b))
1 0 LOAD_GLOBAL 0 (pow)
3 LOAD_FAST 0 (a)
6 LOAD_FAST 1 (b)
9 CALL_FUNCTION 2
12 RETURN_VALUE
Now you know, and you know how to find out!
To delve any deeper you'd have to inspect the c source for pow.
I'd assume it uses the c exponent operator
--
Bob Gailer
919-636-4239
Chapel Hill NC
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