On 31/01/2012 05:33, Christian Witts wrote:
On 2012/01/31 06:50 AM, Michael Lewis wrote:
I am trying to do a simple test but am not sure how to get around
ASCII conversion of characters. I want to pass in y have the function
test to see if y is an integer and print out a value if that integer
satisfies the if statement. However, if I pass in a string, it's
converted to ASCII and will still satisfy the if statement and print
out value. How do I ensure that a string is caught as a ValueError
instead of being converted?
def TestY(y):
try:
y = int(y)
except ValueError:
pass
if y < -1 or y > 1:
value = 82
print value
else:
pass
--
Michael J. Lewis
mjole...@gmail.com <mailto:mjole...@gmail.com>
415.815.7257
_______________________________________________
Tutor maillist -Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
If you just want to test if `y` is an integer you can do so with
`type(y) == int`, and to get the ASCII value of a character you can use
`ord` like `ord('a') == 97`. And how to avoid your ValueError with a bad
conversion, do your type checking before hand.
Hope that helps.
--
Christian Witts
Python Developer
//
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
The test of y would not normally be written as it is, comparisons can be
chained see http://docs.python.org/reference/expressions.html#not-in.
Also Python tends to use EAFP rather than LBYL see
http://docs.python.org/glossary.html.
--
Cheers.
Mark Lawrence.
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
